CBSE Class 11-science Answered
7th numerical
Asked by lovemaan5500 | 04 Oct, 2018, 06:32: PM
Expert Answer
expanded volume of mercury = V×γ×ΔT = 256×1.8×10-4 × 80 = 3.686 cm3........................(1)
where V is volume before heating, γ is volume expansion coefficient and ΔT is increase in temperature.
expansion of glass = Vg×γg×ΔT = 256×3×4×10-6 ×80 = 0.246 cm3 ...........................(2)
subscript g stands for glass. we considered that volume expansion coefficient is three times of linear expansion coefficient
overflowing volume of mercury = 3.686-0.246 = 3.42 cm3
Answered by Thiyagarajan K | 05 Oct, 2018, 12:41: AM
CBSE 11-science - Physics
Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERT