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CBSE Class 11-science Answered

5th?
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Asked by smanishkumar2002 | 30 Jun, 2018, 09:00: PM
answered-by-expert Expert Answer
 
Let us assume the meter scale length is L for the calculation purpose.
Let K be the mass of the scale per unit length, K = M/L.
Consider a small segment dl at a distance l from the hinge as shown in figure. 
It can be seen from figure the segment dl is raised by a height l/2 .
 
potential energy dU of the segment dl is given by, dU = K×dl×g×( l /2 ) = K×(g/2)×l×dl
 
potential energy of the full metre-scale is given by

begin mathsize 12px style U space equals space integral d u space equals space K cross times g over 2 integral subscript 0 superscript L l cross times d l space equals space K cross times g over 2 cross times L squared over 2 space equals M over L cross times g over 2 cross times L squared over 2 equals space 1 fourth M cross times g cross times L end style
Let us substitute the values for M, g and L  ; U = (1/4)×600×10-3 ×10×1 = 1.5 J

Answered by Thiyagarajan K | 30 Jun, 2018, 11:07: PM
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CBSE 11-science - Physics
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Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
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Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
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CBSE 11-science - Physics
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Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
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Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
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