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CBSE Class 12-science Answered

10.18 ques plz
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Asked by lovemaan5500 | 31 Dec, 2019, 04:58: PM
answered-by-expert Expert Answer
When Alkyl chloride is treated with aq. KOH- It is a nucleophilic substitution reaction. KOH releases OH- ion in aquous medium and this OH- ion replaces Cl- and alcohol is formed.
 
RCl + aq. KOH --------> ROH + KCl
 
When Alkyl chloride is treated with alcoholic KOH- It is a beta-elimination reaction. Alcoholic KOH produces alkoxide ion (RO_)  ion which is a strong base, it removes hydrogen from beta-Carbon of alkyl chloride and alkene is formed.
Answered by Ravi | 31 Dec, 2019, 06:00: PM
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