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0.52 g gluoe is dissolved in 80.2 g of water, calcula the boiling point of the solution. (kb or water in 0.52kg mol^-1)

Asked by Sunny Acharjee 3rd March 2013, 7:54 PM
Answered by Expert
Answer:
ΔTb = Kb x Wb x 1000  / Mb  x WA.
Given : 
 
Kb = 0.52   , WB = 0.52 g , Mb = 180g ( C6H12O6)  , 80.2 g
 
ΔTb = answer of the above.
Boiling point of the solution = ΔTb ( the answer above) + 100 °( boiling point of water)
Answered by Expert 4th March 2013, 8:06 PM
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