Why is FeO(s) not formed in the stchiometric composition?

Q: Why is FeO(s) not formed in the stchiometric composition?

In FeO crystals some Fe 2+ cations are replaced by Fe 3+ ions. Two Fe 3+ ions replaces two Fe 2+ ions to make up for the loss of positive charge. Due to this there is less amount of metal as compared to stoichiometric proportion.

Asked by Preethu S | 14th Oct, 2014, 08:38: PM

Expert Answer:

In FeO crystals some Fe²⁺ cations are replaced by Fe³⁺ ions. Two Fe³⁺ ions replaces two Fe²⁺ ions to make up for the loss of positive charge. Due to this there is less amount of metal as compared to stoichiometric proportion.

Why is FeO(s) not formed in the stchiometric composition?

Asked by Preethu S | 14th Oct, 2014, 08:38: PM

In FeO crystals some Fe²⁺ cations are replaced by Fe³⁺ ions. Two Fe³⁺ ions replaces two Fe²⁺ ions to make up for the loss of positive charge. Due to this there is less amount of metal as compared to stoichiometric proportion.

Answered by Arvind Diwale | 15th Oct, 2014, 08:19: AM

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Why is FeO(s) not formed in the stchiometric composition?

Asked by Preethu S | 14th Oct, 2014, 08:38: PM

In FeO crystals some Fe2+ cations are replaced by Fe3+ ions. Two Fe3+ ions replaces two Fe2+ ions to make up for the loss of positive charge. Due to this there is less amount of metal as compared to stoichiometric proportion.

Answered by Arvind Diwale | 15th Oct, 2014, 08:19: AM

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In FeO crystals some Fe²⁺ cations are replaced by Fe³⁺ ions. Two Fe³⁺ ions replaces two Fe²⁺ ions to make up for the loss of positive charge. Due to this there is less amount of metal as compared to stoichiometric proportion.