NEET Class neet Answered

Let two charges 1 μC and 2 μC are placed at points A and B which are 1 m apart.

Let C be center between A and B . Let E₁ be the electric field due to 1 μC charge at A and

E₂ be the electric field due to 2 μC charge at B .

E₁ and E₂ are in opposite direction to each other as shown in figure.

Electric field E at a point P which is at a distance d from charge q  is

E = K × q/d²

where K = 1/(4πε_o) = 9 × 10⁹ N m² C^-2 is Coulomb's constant

E₁ =  [ 9 × 10⁹ × ( 1 × 10^-6 ) ] / (0.5)²  N/C =  36 × 10³  N/C

E₂ =  - [ 9 × 10⁹ × ( 2 × 10^-6 ) ] / (0.5)²  N/C =  -72 × 10³  N/C

Magnitude of net electric field = | E₁ + E₂ | = 3.6 × 10⁴ N/C