NEET Class neet Answered
two point charges are seperated by a distance r in vaccum then force on each charge is f now charges are dipped in liquod of dielectric er what showld be the distance between the forces so that force does not change
Asked by abulkalam70174 | 18 Aug, 2022, 18:32: PM
Let the point charges be q1 and q2 that are separated by a distance r.
Electrostatic force f is given as
![begin mathsize 14px style f space equals space fraction numerator q subscript 1 q subscript 2 over denominator 4 pi epsilon subscript o r squared end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/0f60d36d6b500c1825f301aaae3ace43.png)
Now if these same two charges are in a dielectric medium of dielectric constant εr and
force between them is same as given in eqn.(1)
Then we have
![begin mathsize 14px style f space equals space fraction numerator q subscript 1 q subscript 2 over denominator 4 pi epsilon subscript o space epsilon subscript r space d squared end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/2d880de1704f4241c7452e382a046bed.png)
where d is distance between charges in dielectric medium
from eqn.(1) and (2) , we get
![begin mathsize 14px style d space equals space fraction numerator r over denominator square root of epsilon subscript r end root end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/face15d584cb46099fed531b39d9bb8e.png)
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