Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

Two masses m and 3m are suspended from a light frictionless pulley with the help of a massless string.if the system is set free find the acceleration of the centre of mass

Asked by Debdulal | 27 Sep, 2019, 02:40: PM
Expert Answer
Figure shows the coordinate system for finding the acceleration of centre of mass of system
that consists of two blocks of mass m and 3m respectively.
 
Let d is the diameter of pulley or distance between strings on both side
 
x-coordinate of centre of mass ( in metre ) = [ m×(d/2) + 3m×(d/2) ] /(m+3m) = d/4  
 
magnitude of acceleration of blocks ( in m/s2 ) = [( 3m - m )/(m+3m) ] g = g/2  m/s2
 
direction of acceleration is +y direction for block of mass m and -y direction for block of mass 3m
 
Hence acceleration of block of mass ( in m/s2 ) = [ m×a - 3m×(-a) ](m+3m) = (-a/2 ) = -g/4
 
negative sign in the above relation indicates, acceleration is downward
Answered by Thiyagarajan K | 28 Sep, 2019, 09:52: AM
CBSE 11-science - Physics
Asked by ubarhandepramod | 21 Nov, 2022, 03:49: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by ankurgoyal616 | 27 Sep, 2022, 03:07: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by mahekacharya87 | 20 Sep, 2022, 10:41: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by rk274268 | 05 Aug, 2022, 01:19: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by halderishan008 | 30 Jul, 2022, 07:28: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by Kattaithihaas | 24 Jul, 2022, 01:23: PM
ANSWERED BY EXPERT
Season Break Offer!
Get 60% Flat off instantly.
Avail Now
×