Two balls are dropped to the ground from different heights. one ball is dropped two second after the other but both hit the ground at the same time if the first ball takes 6 second to reach the ground then what is the initial difference between their heights take g is equal to 10 metre per second square

Asked by debargharoy057 | 25th Sep, 2021, 09:48: AM

Expert Answer:

Let h1 be the height from which first ball is dropped . Let h2 be the height from which second ball is dropped .
 
Let h1 > h2 . Since both the balls reached ground at same time , Second ball is dropped later.
 
Since first ball took 6 s to reach ground , we have 
 
h1 = (1/2) g t2 = (1/2) × 10 × 36 = 180 m
 
Since second ball took 4 s to reach ground , we have 
 
h2 = (1/2) g t2 = (1/2) × 10 × 16 = 80 m
 
Height difference = h1 - h2 = ( 160 - 80 ) = 80 m

Answered by Thiyagarajan K | 25th Sep, 2021, 02:31: PM