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CBSE Class 9 Answered

A body moving with uniform acceleration  travels 84m in 6seconds and 264m in 11seconds.  Find acceleration and initial velocity? (In detail)
Asked by sagrawal0081 | 18 Aug, 2023, 05:04: PM
answered-by-expert Expert Answer
Distance S moved in time duration of t seconds is
 
begin mathsize 14px style S space equals space u space t space plus space 1 half space a space t squared end style . . . . . . . . . . . . . . . . . . . (1)
where u is initial velocity and a is acceleration.
 
If distance moved in 6 seconds is 84 m , then we get from eqn.(1)
 
begin mathsize 14px style 64 space equals space 6 space u space plus space 0.5 space asterisk times space a space asterisk times space 6 to the power of 2 to the power of space end exponent space end style
begin mathsize 14px style 6 space u space plus space 18 space a space equals space 84 end style . . . . . . . . . . . . . . .  (2)

similarly , If distance moved in 11 seconds is 264 m , then we get from eqn.(1)
 
begin mathsize 14px style 264 space equals space 11 space u space plus space 0.5 space asterisk times space a space asterisk times space 121 end style
 
begin mathsize 14px style 11 space u space plus space 60.5 space a space equals space 264 end style .........................(3)
 
By solving eqn.(2) and eqn.(3) , we get
 
initial velocity u = 2 m/s and acceleration a = 4 m/s
 

 
 
 
Answered by Thiyagarajan K | 19 Aug, 2023, 10:01: AM
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