CBSE Class 9 Answered
A body moving with uniform acceleration travels 84m in 6seconds and 264m in 11seconds. Find acceleration and initial velocity? (In detail)
Asked by sagrawal0081 | 18 Aug, 2023, 17:04: PM
Distance S moved in time duration of t seconds is
![begin mathsize 14px style S space equals space u space t space plus space 1 half space a space t squared end style](https://images.topperlearning.com/topper/tinymce/cache/3420e813990c4097656527dfd0bf9ce8.png)
where u is initial velocity and a is acceleration.
If distance moved in 6 seconds is 84 m , then we get from eqn.(1)
![begin mathsize 14px style 64 space equals space 6 space u space plus space 0.5 space asterisk times space a space asterisk times space 6 to the power of 2 to the power of space end exponent space end style](https://images.topperlearning.com/topper/tinymce/cache/1839dee72ee6a8db14f021b910aa92b2.png)
![begin mathsize 14px style 6 space u space plus space 18 space a space equals space 84 end style](https://images.topperlearning.com/topper/tinymce/cache/34e2069dafba1b154ff1adca30c9cf54.png)
similarly , If distance moved in 11 seconds is 264 m , then we get from eqn.(1)
![begin mathsize 14px style 264 space equals space 11 space u space plus space 0.5 space asterisk times space a space asterisk times space 121 end style](https://images.topperlearning.com/topper/tinymce/cache/da952046ad07b0adbc1c8dc6dbc6f6c1.png)
![begin mathsize 14px style 11 space u space plus space 60.5 space a space equals space 264 end style](https://images.topperlearning.com/topper/tinymce/cache/110425d51d28472b5a8de5206fb6b307.png)
By solving eqn.(2) and eqn.(3) , we get
initial velocity u = 2 m/s and acceleration a = 4 m/s
Answered by Thiyagarajan K | 19 Aug, 2023, 10:01: AM
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