NEET Class neet Answered
three call masters of 1 kg are placed at the vertices of an equilateral triangle pqr and a mass of 2 kg is placed at the centroid of the triangle which is at the distance of 2 m from each of the vertices of the triangle the force in Newton acting on the mass of 2 kg is
Asked by luminanto2007 | 19 Feb, 2024, 10:45: AM
Expert Answer
Figure shows three 1 kg masses are placed at vertex of equilateral triangle and 2 kg mass at centroid of equilateral triangle.
Let origin of coordinate system is at centroid of triangle.
we are given that distance between centroid and each vertex is 2 m .
As shown in figure , each force F is the gravitational force of attraction between 2 kg mass and 1 kg mass
By Newton's law of gravitaion , magnitude of each force F is calculated as
Net force is obtained from the vector sum of the three forces F shown in figure
where are unit vectors along x-axis and y-axis respectively .
From above expression, we get net force Fnet = 0
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