The velocity of a projectile is 10 m/s. At what angle with the horizintal should it be projected so that it covers maximum horizontal distance?

Asked by shobhit_dc | 18th Jan, 2012, 08:40: PM

Expert Answer:

R = (v02sin2?0)/g.
The maximum horizontal range will be achieved when the sin 2? is maximum. The maximum value of a sine function is 1 and this happens for angles of 90°. If 2? = 90°, then ? = 45°.

Answered by  | 19th Jan, 2012, 10:30: AM

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