CBSE Class 11-science Answered
Dear Student,
The path of the projectile is a parabola. And the equation given is also of a parabola. But in simpler terms,
At maximum height, the path of the projectile is parallel to the ground, ie , only horizontal, this means at this point, the path is parallel to the x axis which means that the slope of the line at this point is zero. Now slope is given by differentiation.
So, differentiate the equation to get the slope
dy/dx= a-2bx
at max height , dy/dx= 0 =a-2bx hence x= a/2b
so, the value of y = 2aa/4b -aa/4b = aa/4b
hence the maximum height = aa/4b
Now for the angle of projection is the initial angle that the projectile makes with the x-axis. so the slope of the angle is given by dy/dx
hence tan(initial angle) = dy/dx at x=0
put x=0 in dy/dx above we get
tan(initial angle) = a
hence angle = tan inverse a
hence this is the angle of the projection.
We hope that clarifies your query.
Regards
Team
TopperLearning