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ICSE Class 10 Answered

The shadow of a tower standing on a level ground is found to be 61.59m longer. When the sun altitudes 34°30`then when it is 50°.find the height of the tower.
Asked by priya_dsl | 13 Sep, 2018, 22:38: PM
answered-by-expert Expert Answer
In ΔABC,
tan 50° = AB/CB
1.1917 = AB/CB
CB = AB/1.1917........(i)
In ΔABD,
tan 34.5° = AB/DB
0.6872 = AB/DB......(ii)
Using (i) and (ii)
solve for 
DB = DC + BC
you will get DB = 145.5 and then find AB using (ii) we get AB = 100 m
 
Answered by Sneha shidid | 18 Sep, 2018, 09:35: AM

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