# ICSE Class 10 Answered

**The shadow of a tower standing on a level ground is found to be 61.59m longer. When the sun altitudes 34°30`then when it is 50°.find the height of the tower.**

Asked by priya_dsl | 13 Sep, 2018, 22:38: PM

Expert Answer

In ΔABC,

tan 50° = AB/CB

1.1917 = AB/CB

CB = AB/1.1917........(i)

In ΔABD,

tan 34.5° = AB/DB

0.6872 = AB/DB......(ii)

Using (i) and (ii)

solve for

DB = DC + BC

you will get DB = 145.5 and then find AB using (ii) we get AB = 100 m

Answered by Sneha shidid | 18 Sep, 2018, 09:35: AM

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