THE RANGE OF A PROJECTILE IS 1.5KMWHEN IT IS PROJECTED AT AN ANGLE OF 15 DEGREE WITH HORIZONTAl. WHAT WILL BE ITS RANGE WHEN IT IS PROJECTED AT AN ANGLE OF 45 DEGREE WITH HORIZONTAL?

Let ‘u’ be the velocity of projection. When the angle of projection is 15⁰ the range is 1500 m.

So, using, R = u² sin(2?)/g

1500 = u² sin(2×15)/g

=> u² = (1500 × g)/sin(30)

Now, the angle of projection is 45⁰.

So,

R = u² sin(2×45)/g = u²/g

  = [(1500 × g)/sin(30)]/g

  = 3000 m

  = 3 km