CBSE Class 10 Answered
The radius of curvature of a concave mirror is 12 cm. The image obtained by it is real and has magnification 3/2. Find the object distance and image distance.
Asked by dalwadiguruprasad | 20 Jul, 2019, 21:05: PM
R = 12cm
m = 3/2
Thus, f= 12/2 = 6 cm
![m equals fraction numerator negative v over denominator u end fraction](https://images.topperlearning.com/topper/tinymce/cache/214907dbab4a805a2010e21d46222d88.png)
![3 over 2 equals fraction numerator negative v over denominator u end fraction](https://images.topperlearning.com/topper/tinymce/cache/5fae261c53aa1f0d166d284675b540d9.png)
3u = -2v
Thus, u = -2v/3
3u + 2v =0
By mirror formula,
1/f = 1/ v + 1/ u
Thus,
1/ (-6) = 1/ (v) + 1/(-2v/3)
Solving this we get,
v = 3 cm
Thus,
3u = -2 × 3
Thus,
u = - 2 cm
Thus, image distance is 3 cm and object distance is 2cm
Answered by Shiwani Sawant | 21 Jul, 2019, 00:28: AM
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