CBSE Class 12-science Answered
the magniuifying power of a telescope is 9. when it adjusted for parallel rays the didtance b/w the eye piece and objective lens is 20cm find the focal length of both lenses
Asked by akgujrati04 | 22 Aug, 2020, 07:06: PM
Expert Answer
Let focal lengths of objective and eyepiece be fo and fe respectively.
fo + fe = 20 ...(1)
Magnifying power of telescope is given as,
fo/fe = 9
Thus,
fo = 9fe...(2)
Thus,
9fe+fe = 20
10fe = 20
fe= 2 cm
From eq(2),
fo=9x2 = 18 cm
Answered by Shiwani Sawant | 23 Aug, 2020, 12:22: AM
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