NEET Class neet Answered
the electric field due to a positive charge at a distance 2m is 4N\c it's magnitude at distance of 4m will be
Asked by siddarthamayuri | 23 May, 2022, 19:47: PM
Electric field E is inversely proportional to square of distance d .
E
( 1/ d2 )
![begin mathsize 14px style proportional to end style](https://images.topperlearning.com/topper/tinymce/cache/a1d297e56ce9d5553b36ea9cc6dd4809.png)
Let E1 = 4 N/C is electrical field at distance d1 = 2 m
Let E2 be the electric field at distance d2 = 4 m
( E2 / E1 ) = ( d12 / d22 )
E2 = E1 ( d12 / d22 ) = 4 × ( 22 / 42 ) = 1 N/C
Answered by Thiyagarajan K | 23 May, 2022, 20:46: PM
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