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the electric field due to a positive charge at a distance 2m is 4N\c it's magnitude at distance of 4m will be
Asked by siddarthamayuri | 23 May, 2022, 07:47: PM
Expert Answer
Electric field E is inversely proportional to square of distance d .
 
E begin mathsize 14px style proportional to end style ( 1/ d2 )
 
Let E1 = 4 N/C is electrical field at distance d1 = 2 m
 
Let E2 be the electric field at distance d2 = 4 m
 
( E2 / E1 ) = ( d12 / d22 )
 
E2 = E1 ( d12 / d22 ) = 4 × ( 22 / 42 )  = 1 N/C
Answered by Thiyagarajan K | 23 May, 2022, 08:46: PM
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