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CBSE Class 11-science Answered

The de Broglie wavelength of an electron travelling with 20% of velocity of light is nearly equal to
Asked by arushidabhade | 13 Aug, 2019, 01:32: PM
Expert Answer
Velocity of light = 3×108 m/s
 
20% of velocity of light = fraction numerator 20 cross times 3 cross times 10 to the power of 8 over denominator 100 end fraction
                                   =6×107 m/s
 
Mass of electron =9.1 ×10−31 kg
 
We know, wavelength λ can be calculated as,
 
straight lambda equals straight h over mv space space equals fraction numerator 6.636 cross times 10 to the power of negative 34 end exponent over denominator 9.11 cross times 10 to the power of negative 31 end exponent cross times 6 cross times 10 to the power of 7 end fraction straight lambda equals 1.21 cross times 10 to the power of negative 11 end exponent space straight m
 
Wavelength of electron is 1.21×10−11 m.
Answered by Varsha | 13 Aug, 2019, 03:43: PM

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