CBSE Class 11-science Answered
The ceiling of a long hall is 25 m high. What is the maximum horizontal distance of a ball thrown with a speed of 40 metre per second can go without hitting the ceiling of the hall.
Asked by tps.mjmdr | 09 Jul, 2018, 08:12: PM
Expert Answer
Let us get the angle of projection α so that the ball will just touch the ceiling of height 25 m.
we use the formula u2sin2α = 2×g×h
where u is projection velocity and h is vertical height that is 25 m.
we have, sin2α = (2×10×25) / (40×40) = 5/16, or α = 34º
Range of projectile = (u2 sin2α ) / g = (40×40×sin68) / 10 = 148 m
Answered by Thiyagarajan K | 10 Jul, 2018, 09:47: PM
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