THE 6TH TERM OF AN A.P. IS 16TH AND THE 14TH TERM IS 32. DETERMINE THE 36TH TERM

 

Asked by burhanshaheen | 12th Sep, 2018, 09:48: AM

Expert Answer:

Hint-
Use the formula of 'terms' of an AP.
 
Tn = a + (n-1)d
 
'a' = first term
'd'= common difference
 
In the Q,
6th term is 16
14th term is 32.
 
Compare both the terms.
a6 = 16 = a + 5d
a14 = 32 = a + 13d,
 
We get,
d = 2
and a = 6.
 
Now, T36 will be a + 35d.
 
Substitute the values of 'a' and  'd' and get the solution.
 
 
 
 

Answered by  | 12th Sep, 2018, 11:06: AM