Structure of a mixed oxide is CCP. The unit cell is composed of oxide ion. One fourth of the tetrahedral voids are occupied by divalent metal A & the octahedral voids are occupied by monovalent metal B. What will be the formula of the solid?
 
 

Asked by Kalita Padmanath | 11th May, 2017, 01:24: PM

Expert Answer:

Number (N) of atoms in ccp = 4=O2-

Hence no. of tetrahedral holes = 2 x N = 2 x 4= 8

No. of A2+ ions = 8 x ¼ =2

No. of octahedral voids = No. of B+ ions = n = 4

Ratio of O2- : A+2: B+ =4: 2: 4=2: 1: 2

Hence the formula of oxide = AB2O2

Answered by Vaibhav Chavan | 11th May, 2017, 04:26: PM