In a cubic lattice A atoms having FCC arrangement B atoms are at body centers and C atoms are at alternate edge centers . The formula of the unit cell will be ;

 

Asked by prakriti12oct | 5th Aug, 2019, 12:08: AM

Expert Answer:

We know that,  Number of atoms in FCC arrangement =4
                       Number of atoms in BCC arrangement=2
 
There are 12 edges in a cubic structure and contribtion of atom on each edge is 1/4
S o space N u m b e r space o f space a t o m s space i n space a l t e r n a t e space e d g e equals 1 fourth cross times 6
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals 3 over 2

N u m b e r space o f space a t o m s space o f space A equals 4
N u m b e r space o f space a t o m s space o f space B equals 2
N u m b e r space o f space a t o m s space o f space C equals 3 over 2

S o space f o r r u l a space w i l l space b e colon
A subscript 4 B subscript 2 C subscript bevelled 3 over 2 end subscript
equals A subscript 8 B subscript 4 C subscript 3

Answered by Ravi | 13th Aug, 2019, 11:09: AM