Analysis shows that nickel oxide has the formula ni 0.98 o1.00. What fractions of nickel exist as ni 2+ and ni 3+ ions?

Asked by Saransekar407 | 11th Mar, 2019, 06:51: PM

Expert Answer:

Given formula is Ni0.98O1.0
 
the ratio of Ni : O = 98 : 100 which means for 100 atoms of oxygen there are 98 atoms of nickels are present.
 
Let us consider the number of atoms of Ni2+ = x hence  the number of atoms of Ni3+ = 98 - x
 
Charge on Ni = charge on O 
3(98-x) + 2x = 2(100)
 
294 - 3x + 2x = 200
-x = -94
x = 94
 
 
Percentage space of space Ni to the power of 2 plus end exponent space equals space fraction numerator atoms space of space Ni to the power of 2 plus end exponent space over denominator Total space number space of space atoms space of space Ni end fraction space cross times space 100

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Percentage of Ni+3 = 100 - Ni2+
                            = 100 - 96
                            = 4 %

Answered by Ramandeep | 11th Mar, 2019, 07:13: PM