CBSE Class 12-science Answered
Analysis shows that nickel oxide has the formula ni 0.98 o1.00. What fractions of nickel exist as ni 2+ and ni 3+ ions?
Asked by Saransekar407 | 11 Mar, 2019, 18:51: PM
Given formula is Ni0.98O1.0
the ratio of Ni : O = 98 : 100 which means for 100 atoms of oxygen there are 98 atoms of nickels are present.
Let us consider the number of atoms of Ni2+ = x hence the number of atoms of Ni3+ = 98 - x
Charge on Ni = charge on O
3(98-x) + 2x = 2(100)
294 - 3x + 2x = 200
-x = -94
x = 94
![Percentage space of space Ni to the power of 2 plus end exponent space equals space fraction numerator atoms space of space Ni to the power of 2 plus end exponent space over denominator Total space number space of space atoms space of space Ni end fraction space cross times space 100
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 94 over 98 cross times 100
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space 96 space percent sign](https://images.topperlearning.com/topper/tinymce/cache/f2c99ca3e7ed239b19e6e65c6ee9cd84.png)
Percentage of Ni+3 = 100 - Ni2+
= 100 - 96
= 4 %
Answered by Ramandeep | 11 Mar, 2019, 19:13: PM
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