JEE Class main Answered
solution please
Asked by piyurawriya | 24 Apr, 2024, 12:46: PM
Expert Answer
= (x-2) [ (3x-4)(10x-17) - (4x-5)(5x-8) ] -(2x-3) [(2x-3)(10x-17)-(4x-5)(3x-5) ] + (3x-4) [(2x-3)(5x-8) -(3x-4)(3x-5) ]
= (x-2) [ 10x2 -34x +28 ] - (2x-3) [ 8x2 - 19x -20 ] + (3x-4) [ x2 - 4x -20 ]
= [ 10x3 - 54 x2 + 96x - 56 ] - [ 16 x3 - 62 x2 +17 x +60 ] + [ 3 x3 -16 x2 -44 x + 80 ]
= - 3 x3 - 8 x2 + 35x - 36
Hence B = -8 , C = 35
B+C = 27
Answered by Thiyagarajan K | 25 Apr, 2024, 06:31: PM
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