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maths sum
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Asked by keerthananukala2007 | 02 May, 2024, 11:32: AM
sec2x -2 tan x = 4
1+tan2x - 2 tan x = 4
(1-tan x)2 = ( ± 2 )2
hence , we get , (1-tan x ) = ± 2
if ( 1- tanx ) = +2
tan x = -1
x = - π/4 rad
if (1- tanx ) = -2
tan x = 3
x = 1.25 rad
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argument θ of above complex number is
Hence ( 1 - a2 ) = 0 or a = ± 1
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