JEE Class main Answered
doubt
Asked by ishansheoran7 | 10 May, 2024, 04:42: PM
Expert Answer
Let ( sinθ + cosecθ ) = α
( sinθ + cosecθ )5 = sin5θ + 5C1 sin4θ cosecθ + 5C2 sin3θ cosec2θ + 5C3 sin2θ cosec3θ + 5C4 sinθ cosec4θ + cosec5θ
( sinθ + cosecθ )5 = sin5θ + cosec5θ + 5 ( sin3θ + cosec3θ ) + 10 ( sinθ + cosecθ )
sin5θ + cosec5θ = ( sinθ + cosecθ )5 - 5 ( sin3θ + cosec3θ ) - 10 ( sinθ + cosecθ )
sin5θ + cosec5θ = ( sinθ + cosecθ )5 - 5 ( sinθ + cosecθ ) ( sin2θ + 3 (sinθ + cosecθ ) + cosec2θ) - 10 ( sinθ + cosecθ )
sin5θ + cosec5θ = ( sinθ + cosecθ )5 - 5 ( sinθ + cosecθ ) [ (sinθ + cosecθ )2 - 2 +3 (sinθ + cosecθ ) ] - 10 ( sinθ + cosecθ )
sin5θ + cosec5θ = α5 - 5 α [ α2 + 3 α -2 ] - 10 α
sin5θ + cosec5θ = α5 - 5 α3 - 15 α2 = α [ α4- 5 α2- 15 α ]
Answered by Thiyagarajan K | 10 May, 2024, 08:08: PM
JEE main - Maths
Asked by pandu.munganda | 10 May, 2024, 11:00: AM
ANSWERED BY EXPERTJEE main - Maths
Asked by keerthananukala2007 | 02 May, 2024, 11:32: AM
ANSWERED BY EXPERTJEE main - Maths
Asked by veerababukoppisettiveerababu3 | 17 Apr, 2024, 05:49: PM
ANSWERED BY EXPERTJEE main - Maths
Asked by rahulkumarbsc73 | 09 Apr, 2024, 04:33: PM
ANSWERED BY EXPERTJEE main - Maths
Asked by srinivaskarri79 | 08 Apr, 2024, 09:53: PM
ANSWERED BY EXPERTJEE main - Maths
Asked by prasanthimaddula7 | 15 Mar, 2024, 08:10: PM
ANSWERED BY EXPERTJEE main - Maths
Asked by amitras0003 | 26 Jan, 2024, 06:53: AM
ANSWERED BY EXPERTJEE main - Maths
Asked by chinnagallakumaraswamy03 | 23 Jan, 2024, 09:39: PM
ANSWERED BY EXPERT
