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TanA=4/3 then SinA=.........whereA€Q3
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Asked by pandu.munganda | 10 May, 2024, 11:00: AM
Left side figure shows the angle A at third quadrant so that tan(A) = -4/-3 = 4/3 .
Hence sin (A) = -4/5
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Right side figure shows the angle A at third quadrant so that sec(A) = 13/5.
Hence cotA = 5/(-12) = - 5/12
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