CBSE Class 8 Answered
Sir, Please ignore my previous question. There was a typo..Now the correct question is; The total number of factors of the number N = 4^11 x 14^5 x 11^2 ?
The Options are (A) 405 (B) 504 (C) 620 (D) 528
This was asked by FTTI-JEE for 8th standard...
Asked by Ramesh | 17 Nov, 2018, 03:34: PM
Expert Answer
Let given number N is expressed in terms of powers of prime number
N = ap × bq × cr ................(1)
where a, b and c are prime numbers. p,q,r are integers.
then number of factors of N = p+q+r+pq+qr+pr+pqr+1 .......................(2)
We have given number N = 411 × 145 × 112 = 222 × (2×7)5 × 112 = 227 × 75 × 112
Hence as per the given formula in eqn.(2), number of factors = 27+5+2+(27×5)+(5×2)+(27×2)+(27×5×2)+1 = 504
Answered by Thiyagarajan K | 19 Nov, 2018, 04:26: AM
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