CBSE Class 8 Answered
Show that an angle of regular octagon is 3/2 times that of square.
Asked by Mohdayaz9921 | 28 Dec, 2018, 12:11: PM
Expert Answer
Sum of the angles of regular polygon of n sides = (n-2)×180
if the angle of regular polygon is θ, then we have, (n-2)×180 = n×α ...........(1)
for octagon, n=8, hence α is obtained from eqn.(1) : α = (6×180)/8 = (3/2)×90 ..........(2)
It can be seen from eqn.(2), angle of regular octagon is 3/2 times that of square.
Answered by Thiyagarajan K | 29 Dec, 2018, 10:43: PM
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