CBSE Class 8 Answered
Show that 74088 is a perfect cube. Also, find the number whose cube is 74088.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
Expert Answer
Resolving 74088 into prime factors, we get:
74088 = 2
2 2 3 3 3 7 7 7 = (2 3 7)3 = 423
Thus, 74088 is a perfect cube.
And, 42 is the number whose cube is 74088.
74088 = 2
2 2 3 3 3 7 7 7 = (2 3 7)3 = 423Thus, 74088 is a perfect cube.
And, 42 is the number whose cube is 74088.
Answered by | 04 Jun, 2014, 03:23: PM
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