NEET Class neet Answered
Seven identical disc arranged hexagonal
Asked by aniketchalak145 | 09 Jul, 2021, 07:58: AM
Expert Answer
Moment of Inertia of central disc , Ic = (1/2) m r2
Moment of inertia Ip of each peripheral disc is determined by parallel axis theorem
Ip = (1/2) m r2 + m (2r)2 = (9/2) m r2
Total Moment of Inertia I = Ic + 6 Ip = (1/2) m r2 + 6 [ (9/2) m r2 ] = (55/2) m r2
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