NEET Class neet Answered

Maximum speed v_max in a curved path is

where μ is static friction coefficient , g is acceleration due to gravity and R radius of curved path .

we get maximum speed in a curved path of radius R = 3 m with static friction coefficient μ = 0.1  as

if the speed of cyclist is 4.5 km/hr , then v = 4.5 × (5/18) m/s = 1.25 m/s

if the speed of cyclist is 9 km/hr , then v = 9 × (5/18) m/s = 2.5 m/s

if the speed of cyclist is 4.5 km/hr, he will not slip because his speed 1.25 m/s is less than maximum safe speed .

if the speed of cyclist is 9 km/hr, he will  slip because his speed 2.5 m/s is greater than maximum safe speed .