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Asked by shanthaswamy.07 | 07 Mar, 2024, 22:36: PM
Maximum speed vmax in a curved path is
where μ is static friction coefficient , g is acceleration due to gravity and R radius of curved path .
we get maximum speed in a curved path of radius R = 3 m with static friction coefficient μ = 0.1 as
if the speed of cyclist is 4.5 km/hr , then v = 4.5 × (5/18) m/s = 1.25 m/s
if the speed of cyclist is 9 km/hr , then v = 9 × (5/18) m/s = 2.5 m/s
if the speed of cyclist is 4.5 km/hr, he will not slip because his speed 1.25 m/s is less than maximum safe speed .
if the speed of cyclist is 9 km/hr, he will slip because his speed 2.5 m/s is greater than maximum safe speed .
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