NEET Class neet Answered

Initial velocity v_i of car = 36 km/hr = 36 × (5/18) m/s = 10 m/s

Final velocity v_f of car = 72 km/hr = 72 × (5/18) m/s = 20 m/s

if the wheel radius is R =25 cm ,

then inital angular velocity of rotation of wheel, ω_i = v_i / R = (10 / 0.25) rad/s = 40 rad/s

Final angular velocity of rotation of wheel, ω_f = v_f / R = (20 / 0.25) rad/s = 80 rad/s

if angular velocity changes in 10 s , then angular acceleration α is

Angular displacement θ in 10 s is calculated from the equation of motion " θ = ω_i t + (1/2) α t² "

Number n of revolution is

n = 600 / (2π ) = 95.5