NEET Class neet Answered

Above figure shows the forces acting on mass m when it is at equilibrium.

T is tension force acting along the rope that is resolved horizontally  ( T sinθ )

and vertically ( T cosθ ) as shown in figure , where θ is the angle made by rope with vertical

Vertical component of tension force balances the weight mg and horizontal component of

tension force balance the applied force F .

Hence we get

T sinθ = F ........................ (1)

T cosθ = mg  ....................(2)

By dividing eqn.(1) by eqn.(2) , we get

tanθ = F / (mg) = 60 / ( 8 × 9.8 ) = 0.765

θ = tan^-1 ( 0.765 ) = 37.4^o