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CBSE Class 10 Answered

secØ +tanØ=p then find the value of cosecØ in terms of p
Asked by ashuganjoo55 | 25 Feb, 2019, 00:32: AM
answered-by-expert Expert Answer
sec2θ - tan2θ = 1

 hence if secθ + tanθ = p  , then secθ - tanθ = 1/p
 
secθ + tanθ = p  ...................(1)
secθ - tanθ = 1/p ...................(2)
 
By adding the two equations we get,   secθ = (1/2) [ p+(1/p) ]...............(3)
 
begin mathsize 12px style cos theta space equals space fraction numerator 2 p over denominator p squared plus 1 end fraction space space space space space space sin theta space equals space square root of 1 space minus space fraction numerator 4 p squared over denominator open parentheses p squared plus 1 close parentheses squared end fraction end root space space equals space square root of fraction numerator open parentheses p squared plus 1 close parentheses squared minus 4 p squared over denominator open parentheses p squared plus 1 close parentheses squared end fraction end root space equals space square root of open parentheses p squared minus 1 close parentheses squared over open parentheses p squared plus 1 close parentheses squared end root space equals space fraction numerator open parentheses p squared minus 1 close parentheses over denominator open parentheses p squared plus 1 close parentheses end fraction cos e c space theta space equals space fraction numerator open parentheses p squared plus 1 close parentheses over denominator open parentheses p squared minus 1 close parentheses end fraction end style
Answered by Thiyagarajan K | 25 Feb, 2019, 00:59: AM

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