Sample of impure magnesium is reacted wih dilute sulphuric acid to give the respective salt and hydrogen. If 1g of impure sample gave 298.6 cc of hydrogen at s.t.p , calculate the % purity of the sample.
Asked by johncena9384 | 2nd Oct, 2018, 10:45: PM
Impure magnesium is reacted with the dilute sulphuric acid to give magnesium sulphate and hydrogen gas.
The reaction is as,
Mg + H2SO4 → MgSO4 + H2
The purity of the sample is 32%
Answered by Varsha | 3rd Oct, 2018, 10:46: AM
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