QQ5. Two identical blocks A and B each of mass M are connected to each other through light strung. The system is placed on a smooth horizontal floor. When constant force F is applied horizontally on the block A, find the tension in the string.

Asked by sbidipak | 5th Jul, 2017, 07:22: PM

Expert Answer:

begin mathsize 12px style The space acceleration space of space the space system space of space two space blocks space straight A space and space straight B space equals space fraction numerator Force over denominator Total space Mass end fraction
rightwards arrow space straight a space equals space fraction numerator straight F over denominator straight M space plus straight M end fraction space equals space fraction numerator straight F over denominator 2 straight M end fraction
If space we space consider space the space free space body space diagram space of space straight A comma space the space forces space acting space on space it space are space the
rightwards arrow applied space force space straight F space and space
rightwards arrow tension space straight T space on space the space string
end style
begin mathsize 12px style Ma space equals space straight F space minus space straight T
But space we space know space that space straight a space equals space fraction numerator straight F over denominator 2 straight M end fraction
therefore space straight m open parentheses fraction numerator straight F over denominator 2 straight M end fraction close parentheses space equals space space straight F space minus space straight T
straight F over 2 space equals space space straight F space minus space straight T
therefore space straight T space equals space straight F over 2 end style

Answered by Yashvanti Jain | 6th Jul, 2017, 12:42: PM