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QQ5. Two identical blocks A and B each of mass M are connected to each other through light strung. The system is placed on a smooth horizontal floor. When constant force F is applied horizontally on the block A, find the tension in the string.

Asked by sbidipak | 05 Jul, 2017, 07:22: PM
answered-by-expert Expert Answer
begin mathsize 12px style The space acceleration space of space the space system space of space two space blocks space straight A space and space straight B space equals space fraction numerator Force over denominator Total space Mass end fraction rightwards arrow space straight a space equals space fraction numerator straight F over denominator straight M space plus straight M end fraction space equals space fraction numerator straight F over denominator 2 straight M end fraction If space we space consider space the space free space body space diagram space of space straight A comma space the space forces space acting space on space it space are space the rightwards arrow applied space force space straight F space and space rightwards arrow tension space straight T space on space the space string end style
begin mathsize 12px style Ma space equals space straight F space minus space straight T But space we space know space that space straight a space equals space fraction numerator straight F over denominator 2 straight M end fraction therefore space straight m open parentheses fraction numerator straight F over denominator 2 straight M end fraction close parentheses space equals space space straight F space minus space straight T straight F over 2 space equals space space straight F space minus space straight T therefore space straight T space equals space straight F over 2 end style
Answered by Yashvanti Jain | 06 Jul, 2017, 12:42: PM

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