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CBSE Class 11-science Answered

Q5
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Asked by piyush07varahney | 06 May, 2020, 06:09: PM
answered-by-expert Expert Answer
To find this error, we note the division of the vernier scale coinciding with any division of the main scale. The number of this vernier division is subtracted from the total number of divisions on the vernier scale and then the difference is multiplied by the least count.
 
Zero error = -(10 - 3) x LC = -7 x 0.1 mm = - 0.7 msd (Since, 9 MSD - 10 VSD)
 
Now, 
 
Correct reading = Observed reading - Zero error (along with the sign) 
 
= 5.4 mm - (0.7)mm = 6.1 mm 
 
Then main scale reading would have been 6.1 mm 
And coinciding division of vernier scale would be 1st
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