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Asked by  | 30th Jul, 2012, 03:42: PM

Expert Answer:

LHS = tanA +[ [tanA+sqrt3] / [1-{(sqrt3)tanA)}] ] +[ [tanA-sqrt3] / [1+[sqrt3}tanA ] ]

           = tanA + [8tanA /(1-3tan2A)]

           = 9tanA-3tan3A / [1-3tan2A]

           = 3tan3A = RHS

Answered by  | 30th Jul, 2012, 04:25: PM

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