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CBSE Class 11-science Answered

asec theta +btan theta=1 asec theta- btan theta=1 a^2(b^2+4)=
Asked by sreyas.katuri | 23 Sep, 2023, 07:12: AM
answered-by-expert Expert Answer
Given: asec theta +btan theta=1 asec theta- btan theta=5
To find: a^2(b^2+4)
asec straight theta space plus space btan straight theta space equals space 1 rightwards double arrow fraction numerator straight a plus bsin straight theta over denominator cos straight theta end fraction equals 1 rightwards double arrow straight a plus bsin straight theta equals cos straight theta space space space... space left parenthesis straight I right parenthesis asec straight theta space minus space btan straight theta space equals space 5 rightwards double arrow fraction numerator straight a minus bsin straight theta over denominator cos straight theta end fraction equals 5 rightwards double arrow straight a minus bsin straight theta equals 5 cos straight theta space space space... space left parenthesis II right parenthesis Adding space left parenthesis straight I right parenthesis space and space left parenthesis II right parenthesis comma space we space get 2 straight a equals 6 cos straight theta rightwards double arrow straight a equals 3 cos straight theta rightwards double arrow 3 cos straight theta minus bsin straight theta equals 5 cos straight theta space rightwards double arrow straight b equals negative 2 cot straight theta straight a squared open parentheses straight b squared plus 4 close parentheses equals 9 cos squared straight theta open parentheses 4 cot squared straight theta plus 4 close parentheses equals 36 space cos squared straight theta open parentheses cot squared straight theta plus 1 close parentheses equals 36 space cos squared straight theta space cosec squared straight theta equals 36 space cot squared straight theta equals 36 cross times fraction numerator straight b squared over denominator 4 straight a end fraction equals 9 straight b squared
Answered by Renu Varma | 25 Sep, 2023, 11:30: AM

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