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ICSE Class 10 Answered

Power of electric heater is1200W when connected to240V supply. If the resistivity and area of cross section of wire is 10 to the power minus 5 ohm meter and 0.4mm square . If the radius of one turn is 7 mm . Find the number of turn in present coip
Asked by Pv9018590 | 26 Jun, 2018, 04:30: PM
answered-by-expert Expert Answer
Power  P = V×I = V×(V/R) = V2 / R ............(1)
 
where V is voltage and I is current, hence we have R = V2 / P = (240×240)/1200 = 48Ω.
 
Resistance R begin mathsize 12px style equals space rho space cross times L over A space end style , where ρ is resistivity, L is length and A area of cross section.
Hence begin mathsize 12px style L space equals space R cross times A over rho space equals space 48 cross times fraction numerator 0.4 cross times 10 to the power of negative 6 end exponent over denominator 10 to the power of negative 5 end exponent end fraction space equals space 1.92 space m space equals space 1920 space m m end style
number of turns = Length / (circumference of one turn) = 1920 / (2π×7) = 44 turns
Answered by Thiyagarajan K | 26 Jun, 2018, 05:10: PM
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