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CBSE Class 11-science Answered

Position x of a particle varies with time t as x= at^2 - bt^3. The acceleration will be zero at time t equal to? 
Asked by arushidabhade | 08 Jun, 2019, 07:26: AM
answered-by-expert Expert Answer
position x = at2 - bt3 ;
 
veleocity dx/dt = 2at - 3bt2 ;
 
acceleration  d2x/dt2 = 2a - 6bt  ;  acceleration is zero when  t = 2a/(6b) = a/3b
Answered by Thiyagarajan K | 08 Jun, 2019, 09:51: AM
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