NEET Class neet Answered
plzz solve this
Asked by surabhilakhara7299 | 10 Jul, 2021, 00:49: AM
Expert Answer
Workdone by the force to lift a mass m to a height h = ( m g h )
Workdone by force against friction force = friction force × distance = ( μ m g ) × 
Total workdone W = [ ( m g h ) + ( μ m g ) × ] = (mgh) [ 1 + μ 
]
] = (mgh) [ 1 + μ ]
Answered by Thiyagarajan K | 10 Jul, 2021, 07:51: AM
NEET neet - Physics
Asked by dasmyton | 09 Jul, 2024, 22:46: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by gopalkdch1979 | 19 Jun, 2024, 16:40: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by adeshkulshrestha12 | 30 Dec, 2023, 20:38: PM
ANSWERED BY EXPERT
NEET neet - Physics
Asked by keyasp.unoff | 22 Aug, 2023, 19:05: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by aniket30092005 | 01 Aug, 2023, 20:54: PM
ANSWERED BY EXPERTNEET neet - Physics
Asked by harshs2580 | 04 Nov, 2022, 08:45: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by surabhilakhara7299 | 10 Jul, 2021, 00:49: AM
ANSWERED BY EXPERTNEET neet - Physics
Asked by sibasaimohapatra04 | 13 May, 2021, 20:35: PM
ANSWERED BY EXPERT