NEET Class neet Answered
The answer given is 32J .Please explain i guess it has to do something with t=0 to t=2s little confused please explain
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Asked by nipunverma59 | 29 Mar, 2019, 20:01: PM
Work done by force
W =F.s (scalar product of force and displacement
W = (3ti + 5j).(2t^2i -5j) = 6t^3 -25
Putting the value of the t= 2 sec
W = 6×8 - 25 = 48 -25 = 23Joule
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