NEET Class neet Answered
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Asked by sibasaimohapatra04 | 13 May, 2021, 20:35: PM
Total initial momentum = m1 v1 + m2 v2 = ( 2 × 10 ) + [ 2 × (-20) ] = -20 kg m/s
Perfect inelastic collision means, both masses stick together after collision.
Hence if v is velocity of combined mass after collision ,
then we have , ( m1 + m2 ) v = -20 or v = -20 / 4 = -5 m/s
Initial kinetic energy = (1/2) m1 v12 + (1/2) m2 v22 = ( 0.5 × 2 × 100 ) + ( 0.5 × 2 × 400 ) = 500 J
Kinetic energy after collision = (1/2) [ m1 + m2 ] v2 = 0.5 × 4 × 25 = 50 J
Loss of kinetic energy = ( 500 - 50 ) J = 450 J
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