CBSE Class 11-science Answered
Pls solve it.
Asked by pb_ckt | 07 Jun, 2019, 01:46: PM
Expert Answer
Let us assume after t seconds, cyclist overtake the bus.
Distance travelled by cyclist = speed×time = 20×t m .....................(1)
Distance travelled by bus = (1/2)×a×t2 = (1/2)×2×t2 = t2 m ........................(2)
Since initially cyclist was 96 m behind the bus, we have from eqn.(1) and (2)
t2 = 20×t - 96 or t2 - 20×t + 96 = 0 ...................(3)
By solving eqn.(3) we get t = 8 s or t = 12 s
At t = 8 s, cyclist overtake the bus. At t = 8 s, speed of cyclist is greater than speed of bus.
At t= 12 s , bus will pick up enough speed to overtake the cyclist
Answered by Thiyagarajan K | 07 Jun, 2019, 02:46: PM
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