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CBSE Class 12-science Answered

pls explain
question image
Asked by mufeedatvp2000 | 19 Apr, 2020, 04:20: PM
answered-by-expert Expert Answer
Average intensity of electromagnetic waves is given as, 
I space space equals space 1 half space element of subscript 0 space c space E squared subscript 0 space P over A equals space 1 half space element of subscript 0 space c space E squared subscript 0 space E subscript 0 superscript 2 space equals space fraction numerator 2 P over denominator A element of subscript 0 space c end fraction space E subscript 0 superscript 2 space space space equals space open square brackets fraction numerator 2 cross times 1500 over denominator 4 pi open parentheses 3 close parentheses squared space cross times 8.85 cross times 10 to the power of negative 12 end exponent cross times 3 cross times 10 to the power of 8 end fraction close square brackets space space equals space 10000 space therefore E subscript 0 equals space 100 space V divided by m space 
 
Correct option - (B) 
Answered by Shiwani Sawant | 19 Apr, 2020, 05:18: PM

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