CBSE Class 12-science Answered
pls explain
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Asked by mufeedatvp2000 | 19 Apr, 2020, 16:20: PM
Average intensity of electromagnetic waves is given as,
![I space space equals space 1 half space element of subscript 0 space c space E squared subscript 0 space
P over A equals space 1 half space element of subscript 0 space c space E squared subscript 0 space
E subscript 0 superscript 2 space equals space fraction numerator 2 P over denominator A element of subscript 0 space c end fraction space
E subscript 0 superscript 2 space space space equals space open square brackets fraction numerator 2 cross times 1500 over denominator 4 pi open parentheses 3 close parentheses squared space cross times 8.85 cross times 10 to the power of negative 12 end exponent cross times 3 cross times 10 to the power of 8 end fraction close square brackets space
space equals space 10000 space
therefore E subscript 0 equals space 100 space V divided by m space](https://images.topperlearning.com/topper/tinymce/cache/f401b1d276d7ba616026d8d9734abd90.png)
Correct option - (B)
Answered by Shiwani Sawant | 19 Apr, 2020, 17:18: PM
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