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CBSE Class 10 Answered

Please solve this question 
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Asked by vikasg13.hardware | 04 Sep, 2018, 08:29: AM
answered-by-expert Expert Answer
begin mathsize 16px style Let space straight y space should space be space subtracted space from space fraction numerator begin display style straight x squared plus 2 end style over denominator begin display style straight x minus 1 end style end fraction space to space get space fraction numerator begin display style straight x squared plus 6 straight x minus 1 end style over denominator begin display style straight x squared minus 1 end style end fraction.
fraction numerator straight x squared plus 2 over denominator straight x minus 1 end fraction minus straight y equals fraction numerator straight x squared plus 6 straight x minus 1 over denominator straight x squared minus 1 end fraction
straight y equals fraction numerator begin display style straight x squared plus 2 end style over denominator begin display style straight x minus 1 end style end fraction space minus space fraction numerator begin display style straight x squared plus 6 straight x minus 1 end style over denominator begin display style open parentheses straight x minus 1 close parentheses open parentheses straight x plus 1 close parentheses end style end fraction
straight y equals fraction numerator open parentheses straight x squared plus 2 close parentheses begin display style open parentheses straight x plus 1 close parentheses end style begin display style minus end style begin display style open parentheses straight x squared plus 6 straight x minus 1 close parentheses end style over denominator open parentheses straight x minus 1 close parentheses open parentheses straight x plus 1 close parentheses end fraction
straight y equals fraction numerator straight x cubed plus straight x squared plus 2 straight x plus 2 minus straight x squared minus 6 straight x plus 1 over denominator open parentheses straight x minus 1 close parentheses open parentheses straight x plus 1 close parentheses end fraction
straight y equals fraction numerator begin display style straight x cubed minus 4 straight x plus 3 end style over denominator begin display style open parentheses straight x minus 1 close parentheses open parentheses straight x plus 1 close parentheses end style end fraction
straight y equals fraction numerator open parentheses straight x minus 3 close parentheses begin display style open parentheses straight x minus 1 close parentheses end style over denominator open parentheses straight x minus 1 close parentheses open parentheses straight x plus 1 close parentheses end fraction
straight y equals fraction numerator open parentheses straight x minus 3 close parentheses over denominator open parentheses straight x plus 1 close parentheses end fraction

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Answered by Sneha shidid | 04 Sep, 2018, 03:11: PM
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