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CBSE Class 12-science Answered

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Asked by arjunsah797 | 23 Mar, 2022, 05:23: PM
Expert Answer
Induced EMF as per Faraday's law of induction , E = -dΦ/dt 
 
where Φ = B•A = B A cosθ
 
Φ is magnetic flux , B is magnetic flux density , A is area of loop and
θ is angle between direction of magnetic field and normal to the loop.
 
As we see from figure , angle θ = 180 o because direction of magnetic field and normal to the loop
are parallel but in opposite direction.
 
E = - dΦ/dt = - (dB/dt ) A cos(180) = A (dB/dt )
 
when magnet north pole is moving towards loop of coil, magnetic field increases with respect to time ,
hence (dB/dt) is positive and induced EMF is positive.
 
If induced EMF is positive in the loop , then incuded EMF flows in counterclockwiase direction
in the loop when viewed from magnet side.
 
hence current flows from right to left across resistor as shown in figure.
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By applying similar concept as explained above, when north pole of magnet moves away from loop ,
negative induced current flows in the loop in clockwise direction.
 
hence current flows from left to right across resistor as shown in figure.
Answered by Thiyagarajan K | 23 Mar, 2022, 10:53: PM
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